🌱BUGUNGI SERTIFIKAT ATF MASALA YECHIMI👇
Silovsining 3 ta hujayrada jami 768 ta ATF hosil bo‘ldi ulandan
3/8 birinchi hujayrada 1/8 ikkinchi hujayrada 4/8 uchinchi hujayrada hosil bo‘ldi
Birinchi hujayrada parchalanmay qolgan Sut kislatasi ikkinchi hujayrada parchalanmay qolgan sut kislayadan 3 marta ko‘p uchinchi hujayrada parchalanmay qolgan sut kislata birinchi hujayrada to‘liq parchalangan sut kislatadan 3.5 marta ko‘p
Ikkinchi hujayrada to‘liq parchalangan sut kislata soni birinchi hujayrada chala parchalangan sut kislatadan 15 marta kam
♾♾♾♾♾♾♾♾♾♾♾♾♾♾
YECHIMI👇👇👇👇👇👇
768×3/8=288 (A)
768×1/8=96 (B)
768×1/2=384 (C)
A hujayrada chala parchalangan glukoza x deb olsak.B hujayrada chala parchalangan 3x bo'ladi.
C hujayrada chala parchalangan glukozani 7y deb olsak. A hujayradagi to'liq 2y(7y/2) bo'ladi. B hujayradagi to'liqni topish uchun A hujayradagi chalani 15ga bo'lish kk(3x/15=0.2x). shunda ma'lumotlad quyidagicha
A B C
Chala 3x x 7y
To'liq 7y 0.2x
0.2x×38+x×2=96
x=10
A hujayrada 288ta ATF
3×10×2+2×38y=288
y=3
C hujayrada 384ta ATF
7×3×2=42ATF
384-42=342/38=9 To'liq
Demak...
A 30 6
B 10 2
C 21 9
Ch T
Bandlarda nima so'ragani esimda yo'q
Shuning uchun to'liq va chalani ajratib berdim
𝗕𝗔𝗥𝗖𝗛𝗔𝗚𝗔 𝗨𝗟𝗔𝗦𝗛𝗔𝗠𝗜𝗭🤝
⚡️𝙆𝘼𝙉𝘼𝙇𝙇𝘼𝙍𝙄𝙈𝙄𝙕𝙂𝘼 𝙊𝘽𝙐𝙉𝘼 𝘽𝙊'𝙇𝙄𝙉𝙂👇👇👇👇👇
🌱@BIOLOG_QUIZ_TESTLAR👈
🌱@SERTIFIKAT_MASALA👈
🌱@BIOLOG_50👈
🌱@BIOLOGY_SERTIFIKAT👈
🌱@BIOLOG_QUIZ_TESTLAR👈
𝗥𝗲𝗮𝗸𝘀𝗶𝘆𝗮 𝗴𝗼𝗼𝗼𝗼𝗼𝗼🔥🔥🔥
Silovsining 3 ta hujayrada jami 768 ta ATF hosil bo‘ldi ulandan
3/8 birinchi hujayrada 1/8 ikkinchi hujayrada 4/8 uchinchi hujayrada hosil bo‘ldi
Birinchi hujayrada parchalanmay qolgan Sut kislatasi ikkinchi hujayrada parchalanmay qolgan sut kislayadan 3 marta ko‘p uchinchi hujayrada parchalanmay qolgan sut kislata birinchi hujayrada to‘liq parchalangan sut kislatadan 3.5 marta ko‘p
Ikkinchi hujayrada to‘liq parchalangan sut kislata soni birinchi hujayrada chala parchalangan sut kislatadan 15 marta kam
♾♾♾♾♾♾♾♾♾♾♾♾♾♾
YECHIMI👇👇👇👇👇👇
768×3/8=288 (A)
768×1/8=96 (B)
768×1/2=384 (C)
A hujayrada chala parchalangan glukoza x deb olsak.B hujayrada chala parchalangan 3x bo'ladi.
C hujayrada chala parchalangan glukozani 7y deb olsak. A hujayradagi to'liq 2y(7y/2) bo'ladi. B hujayradagi to'liqni topish uchun A hujayradagi chalani 15ga bo'lish kk(3x/15=0.2x). shunda ma'lumotlad quyidagicha
A B C
Chala 3x x 7y
To'liq 7y 0.2x
0.2x×38+x×2=96
x=10
A hujayrada 288ta ATF
3×10×2+2×38y=288
y=3
C hujayrada 384ta ATF
7×3×2=42ATF
384-42=342/38=9 To'liq
Demak...
A 30 6
B 10 2
C 21 9
Ch T
Bandlarda nima so'ragani esimda yo'q
Shuning uchun to'liq va chalani ajratib berdim
Parchalangan va parchalanmagan sut kislota nisbati, To'liq va chala parchalangan glukoza nisbati bilan bir xil
𝗕𝗔𝗥𝗖𝗛𝗔𝗚𝗔 𝗨𝗟𝗔𝗦𝗛𝗔𝗠𝗜𝗭🤝
⚡️𝙆𝘼𝙉𝘼𝙇𝙇𝘼𝙍𝙄𝙈𝙄𝙕𝙂𝘼 𝙊𝘽𝙐𝙉𝘼 𝘽𝙊'𝙇𝙄𝙉𝙂👇👇👇👇👇
🌱@BIOLOG_QUIZ_TESTLAR👈
🌱@SERTIFIKAT_MASALA👈
🌱@BIOLOG_50👈
🌱@BIOLOGY_SERTIFIKAT👈
🌱@BIOLOG_QUIZ_TESTLAR👈
𝗥𝗲𝗮𝗸𝘀𝗶𝘆𝗮 𝗴𝗼𝗼𝗼𝗼𝗼𝗼🔥🔥🔥