A|. |T→x+250
G| |C→x

x+x+250=1750
2x=1750-250
x=750→G va C orasida H bogʻ
x+250=750+250=1000 A va T

750:3=250 ta G yoki C
1000:2=500 ta A yoki T

A| |T→500\
Jami N=1500 ta
G| |C→250/


DNK--i-RNK--OQSIL
1500. 750. 250

1 ta a-kta ---120 D
250 tasi----x=30 000 D

Oʻqituvchi Rahimberdiyev Sanjarbek