Yechilish usuli:

1) A -o'simlik
uning somatik xromasomalari - 2x
Jinsiy xromasomalari - x ga teng

2) ikkinchi o'simlikniki - 2y
Jinsiysi - y ga teng

3) x - y = 2.143
x + y = 12.143 shu tenglamada

X= 7.143 ga

4) 7.143 % ------- 1
100% ------x- 14, 2n=14 ( bug'doy)

5% --------- 1
100% -----x- 20, 2n=20 (makkajoxori)

5) Bug'doy endospermida autosoma soni 3n=21-3 (18 ✅)

6) Makkajoxori barg og'izchasida 2 ta hujayra bor har birida 20 tadan jami ( 40 ta ✅) xromasomalari bor

Javob: a- 18, b- 40

@matritsatalim