Odilbek Sayfullayev | Shaxsiy Blog

Bu kod 🔓 brute-force usuli orqali parolni topishga harakat qiladi.

📌 Vazifasi
1. 👤 Foydalanuvchi parol kiritadi
2. 🤖 Kod barcha imkoniyatlarni tekshiradi
- 🔍 Belgilar kombinatsiyasini hosil qiladi
- 🔑 Har bir kombinatsiyani parol bilan solishtiradi
3. ✅ Agar parol topilsa, natijani chiqaradi
- ⏳ Necha sekundda topilganini ham ko‘rsatadi
4. ❌ Agar parol topilmasa, xabar beradi

📌 Qanday ishlaydi?
- ⚡️ "abc123" kabi oddiy parollar uchun tez topadi
- 🛡 "aZ9!x" kabi murakkab parollar uchun ko‘proq vaqt talab qiladi
- 🔠 Barcha harflar va raqamlarni ishlatadi (A-Z, a-z, 0-9)
- 📏 Parol uzunligiga qarab avtomatik moslashadi

🚀 Bu kod faqat ilmiy va ta’lim maqsadida ishlatilishi kerak!

import itertools
import string
import time


def brute_force(password, max_length=None, chars=None):
"""
Brute-force orqali parolni topishga harakat qiladi.

:param password: Foydalanuvchi kiritgan parol
:param max_length: Maksimal uzunlik (agar berilmasa, parol uzunligi bilan belgilanadi)
:param chars: Foydalaniladigan belgilar (standart: harflar + raqamlar)
"""
if chars is None:
chars = string.ascii_letters + string.digits # A-Z, a-z, 0-9

if max_length is None:
max_length = len(password) # Parol uzunligi asosida belgilanadi

start_time = time.time()

for length in range(1, max_length + 1):
for attempt in itertools.product(chars, repeat=length):
attempt_password = "".join(attempt)

if attempt_password == password:
end_time = time.time()
print(f"\n[+] Parol topildi: {attempt_password}")
print(f"🕒 Sarflangan vaqt: {end_time - start_time:.2f} sekund")
return

# Har 10,000 ta urinishdan keyin jarayonni ko‘rsatish
if itertools.product(chars, repeat=length).__sizeof__() % 10000 == 0:
print(f"🔍 Testing: {attempt_password}")

print("\n[-] Parol topilmadi.")


# Foydalanuvchi inputi
password = input("🔑 Parolni kiriting: ").strip()
brute_force(password)

500.000 so'mga malware dastur kodini tashlab beraman.

Bugun aksiya 20.000 so'mga tushdi narx👌

Assalomu alaykum do'stlar hozirda Instagram akkaunt login va parolini aniqlab beradigan dastur sotilmoqda.


Phishing qanday ishlaydi? 🎭💀

1️⃣ Soxta sahifa yaratish – Xaker asl Instagram sahifasiga o‘xshash sayt tayyorlaydi.

2️⃣ Qurbonlarni jalb qilish – Soxta sahifa havolasi Email, Telegram, SMS yoki ijtimoiy tarmoqlar orqali tarqatiladi.

3️⃣ Foydalanuvchi ma’lumotlarini o‘g‘irlash – Qurbon login va parolini kiritganda, bu ma’lumot xakerga bot orqali yuboriladi.

4️⃣ Hisobni egallash – Xaker parol bilan kirib, akkauntni boshqarishni qo‘lga oladi.

5️⃣Akkauntni chopish - Xaker akkaunt login va parolni o'zgartirib uni o'zlashtiradi yoki sotib yuboradi.

🗒Eslatma: ❌ Phishing noqonuniy va xavfli !

💲Narxi: 30.000 so'm
👤Murojaat uchun: @corge_11

Happy birthday to me!🎂

Qaysi qit'a eng katta ?

import logging
import asyncio
from aiogram import Bot, Dispatcher, types, F
from aiogram.types import InlineKeyboardMarkup, InlineKeyboardButton, ChatMemberUpdated
from aiogram.filters import Command
from collections import defaultdict

API_TOKEN = "botingiz_tokeni"
CHANNEL_USERNAME = "test_uchun" # Kanal username (@ belgisisiz)

bot = Bot(token=API_TOKEN)
dp = Dispatcher()
logging.basicConfig(level=logging.INFO)


user_activity = defaultdict(int)
visited_users = set()



async def check_subscription(user_id):
try:
member = await bot.get_chat_member(f"@{CHANNEL_USERNAME}", user_id)
return member.status in ["member", "administrator", "creator"]
except Exception as e:
logging.error(f"Obuna tekshirishda xatolik: {e}")
return False



@dp.message(Command("start"))
async def handle_start(message: types.Message):
user_id = message.from_user.id
subscribed = await check_subscription(user_id)

if not subscribed:
keyboard = InlineKeyboardMarkup(inline_keyboard=[
[InlineKeyboardButton(text="🔔 Kanalga obuna bo‘lish", url=f"https://t.me/{CHANNEL_USERNAME}")]
])
await message.answer("Botdan foydalanish uchun kanalga a’zo bo‘ling!", reply_markup=keyboard)
return

if user_id not in visited_users:
visited_users.add(user_id)
await message.answer("🎉 Xush kelibsiz! Bot tayyor.")



@dp.chat_member(ChatMemberUpdated)
async def member_handler(update: ChatMemberUpdated):
if update.new_chat_member.status == "member":
await bot.send_message(update.chat.id, f"👋 {update.new_chat_member.user.full_name} kanalga qo‘shildi!")



@dp.message()
async def track_activity(message: types.Message):
user_id = message.from_user.id
user_activity[user_id] += 1



@dp.message(Command("top1"))
async def most_active_user(message: types.Message):
if not user_activity:
await message.answer("📊 Hali hech kim faol emas.")
return
top_user = max(user_activity, key=user_activity.get)
await message.answer(f"🏆 Eng faol foydalanuvchi: [{top_user}](tg://user?id={top_user}) \\({user_activity[top_user]} xabar\\)", parse_mode="Markdown")




@dp.message(Command("top10"))
async def top_10_users(message: types.Message):
if not user_activity:
await message.answer("📊 Hali hech kim faol emas.")
return

sorted_users = sorted(user_activity.items(), key=lambda x: x[1], reverse=True)[:10]
ranking = "\n".join([f"{i + 1}. [{user_id}](tg://user?id={user_id}) - {count} xabar" for i, (user_id, count) in
enumerate(sorted_users)])
await message.answer(f"🏆 **Eng faol 10 ta foydalanuvchi:**\n{ranking}", parse_mode="Markdown")



@dp.message(Command("stats"))
async def stats(message: types.Message):
chat = await bot.get_chat(f"@{CHANNEL_USERNAME}")
members_count = await chat.get_member_count()
await message.answer(f"📊 Kanal obunachilari soni: {members_count}")



async def main():
await dp.start_polling(bot)


if __name__ == "__main__":
asyncio.run(main())


🔹 Telegram kanallaringiz uchun maxsus bot kodi ! 🚀
✅ Bepul va qulay yechim !

Chatga kirila shaxmat o'ynaymiz.